
| Contents for this page | Related topics | ![]() |
|---|---|---|
|
Introduction Moving source, stationary listener General case Blood flow rates measurements Additional questions |
Doppler effect with light Light and colour 2-D and 3-D wavefronts Wave nature of matter |
Data Glossary |
| Learning Outcomes | ||
| After studying this section, you will be familiar with the Doppler effect with sound and be aware of some of it practical applications. | ||
| Helpful background knowledge | ||
| Introduction to vectors | Addition of vectors | Equations of motion |
Please note: Some links will play sound files. They are labelled with "
". You will need a multimedia computer to play them.
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When a sound source moves relative to a listener, the listener hears hears sound of variable frequency, depending on the relative speed of the source with respect to the listener. For example, if you stand alond a road and an ambulance approaches sounding its siren , you will hear sound of increasing frequency as the ambulance approaches, and decreasing frequency as the ambulance recedes. This is known as the DOPPLER EFFECT after its discoverer, Christian Johann Doppler. |
If the source is moving, the wave front is bunched up in the direction of motion and spread out in the opposite direction:

If fS is the frequency of the sound emitted by the source, then the period, T of the wave will be given by T = 1/fS.
During this time, the source will have moved a distance TvS = cvS/fS.
The wavelength λ is the RELATIVE DISPLACEMENT of the wave with respect to the source:
λ = c/fS - vS/fS = (c - vS)/fS
Which shows why the wavelength in the direction of motion is shorter than for the stationary source, and longer in the opposite direction (vS then being negative).
The stationary listener hears a frequency fo such that fo = c/λ, thus

If a sound source, such as the ambulance described above
, passes by a stationary observer, the pitch (frequency) of the sound will increase according to fo = fs(c/c - vs) as the sound source approaches the observer, and then decrease according to fo = fs(c/c + vs) as the sound source recedes from the observer.
The stationary object has a speed vo = 0, and will receive a frequency f = (c/c - vs). The sound at that frequency is now reflected back towards the original source, which acts as a moving observer, while the stationary object from which the sound is relected acts as a stationary source. The received frequency is fr = f(c + v/c) = fs(c + vs)/(c - vs).
You can try and show that the received frequency after reflection is fr = fs(c - vo)/(c + vo). See below for a medical application in determining the rate of flow of blood in blood vessels.
We will use the following symbols:
fs: frequency of the sound source
fo: frequency of sound as measured by the observer
c: velocity of the sound wave
vs: velocity of the sound source
vo: velocity of the observer.
The general equation that governs fo is:

where the upper signs (shown in red) are for cases where the source and observer APPROACH each other, and the lower signs (shown in blue) are for cases where the source and observer RECEDE from one another. The table below shows how fo is affected in different situations.
| Condition | General equation reduces to | Effect on frequency detected by observer |
|---|---|---|
| Observer and source are both at rest: vs = vs = 0 | fo = fs | No change in detected frequency |
| Stationary observer (vo = 0), source approaching observer | fo = fsc/(c - vs) | fo increases |
| Stationary observer (vo = 0), source receding from observer | fo = fsc/(c + vs) | fo decreases |
| Stationary source (vs = 0), observer moving towards source | fo = fs(c + vo)/c | fo increases |
| Stationary source (vs = 0), observer receding from the source | fo = fs(c - vo)/c | fo decreases |
| Source approaches the observer at velocity vs = c | fo → ∞ | Condition for shock wave |
| Source recedes from the observer at velocity vs = c | fo = fs/2 | Sound now has half the source frequency |
| Observer moves towards stationary source at a velocity vo = c | fo = 2fs | Sound now has double the source frequency |
| Observer moves away from stationary source at a velocity vo = vs | fo = 0 | No sound is detected |
The Doppler effect is used for determining the rate of flow of blood in blood vessels. In the diagram below, blood is flowing from left to right within an artery, at a velocity, v. A crystal ultrasound transmitter sends out a signal at an angle q to the flow, where it is reflected back by blood corpuscles, to be picked up by a crystal receiver.

For low values (< 5º) of θ, cosθ, the component of the sound velocity parallel to the blood flow, approximates to 1. We have here a case of the "listener" (the blood corpuscles) moving away from a stationary source, and thus the frequency, fcorpuscle that will be reflected by the corpuscles will be

For the reflected waves, reflection, the corpuscles are the source and the "listener" is the receiver. The frequency at the receiver will be

from which we get

The flow rate, v, is then readily obtained from a knowledge of the difference between the transmitted and received frequencies, and c, the velocity of sound wave in blood.